# A person pushing a stroller starts from rest, uniformly accelerating at a rate of 0.500 m/s^2. What is the velocity of the stroller after it has traveled 4.75 m?

Sorry, I made a typo.... the problem should say: what is the velocity of the stroller after it has traveled 6.32 m?

Use the formula V = sqrt(2aX),
where a is the acceleration and X is the distance travelled. This formula applies when the initial velocity is zero and the acceleration is constant in one direction..

Thanks! I got +2.51 m/s. Is this right?

Yes, that is what I got also.

## To find the velocity of the stroller after it has traveled a distance of 6.32 m, you can use the formula V = sqrt(2aX), where a is the acceleration and X is the distance traveled.

Given:
Acceleration (a) = 0.500 m/s^2
Distance (X) = 6.32 m

Substituting the given values into the formula:
V = sqrt(2 * 0.500 * 6.32)

Calculating the expression inside the square root:
V = sqrt(6.32)

Taking the square root:
V ≈ 2.514 m/s

Therefore, the velocity of the stroller after it has traveled 6.32 m is approximately 2.514 m/s.

Please note that the value of 2.51 m/s is rounded, but the precise value is 2.514 m/s.

## To find the velocity of the stroller after it has traveled 6.32 m, you can use the formula V = sqrt(2aX), where V is the final velocity, a is the acceleration, and X is the distance traveled.

In this case, the acceleration is given as 0.500 m/s^2, and the distance traveled is 6.32 m. Plugging in these values into the formula, we have:

V = sqrt(2 * 0.500 m/s^2 * 6.32 m)

Calculating the expression inside the square root:

V = sqrt(6.32 m^2/s^2)

V = 2.51 m/s

So, the velocity of the stroller after it has traveled 6.32 m is indeed +2.51 m/s.

Well done!