Angle 1 is supplementary to angle 2. If m<1 = (12x + 6) and m<2 = (4x - 34), what is the value of X and the m<1 ?
m<1 + m<2 = 180 degrees because they are supplementary!
So, 12x+6 + 4x-34 = 180
I imagine you can take it from here.
To find the value of x and m<1, we can set up an equation based on the given information that angle 1 is supplementary to angle 2.
Supplementary angles add up to 180 degrees.
So, we have the equation:
m<1 + m<2 = 180
Substituting the given expressions for m<1 and m<2, we get:
(12x + 6) + (4x - 34) = 180
Simplifying the equation, we combine like terms:
16x - 28 = 180
To isolate the variable x, we will add 28 to both sides of the equation:
16x = 180 + 28
16x = 208
Next, we will divide both sides of the equation by 16 to solve for x:
x = 208 / 16
x = 13
So, the value of x is 13.
To find the value of m<1, we substitute the value of x into the equation for m<1:
m<1 = 12x + 6
m<1 = 12(13) + 6
m<1 = 156 + 6
m<1 = 162
Therefore, the value of x is 13 and m<1 is 162.