# is -2i square root of 2 a solution to x=8?

lets check:

(-2i sqrt 2)^2= -1^2 * 2^2 * i^2 *2

=-8

Answer: no.

## To verify if -2i√2 is a solution to the equation x = 8, we substitute the value into the equation and check if the resulting expression is true:

x = 8

(-2i√2)^2 = 8

First, we square -2i√2. Since squaring a complex number involves squaring both the real and imaginary components, we can simplify as follows:

(-2i√2)^2 = (-2)^2 * (i^2) * (√2)^2

=(-2)^2 * (-1) * 2

= 4 * (-1) * 2

= -8

The result of (-2i√2)^2 is -8, which is not equal to 8. Therefore, -2i√2 is not a solution to the equation x = 8.