f(x)=x^3+4 f=1, f=-1
Are the answer to this 5 and 3
I must not understand
f(x)=x^3+4
f=1
f(1)=(1)^3+4
(1)^3=1 because 1X1X1=1
1+4=5
so f(1)=5
f=-1
f(-0)=(-1)^3+4
(-1)^3=-1
because -1x-1x-1=1x-1=-1
-1+4=3
so f(-1)=3
To find the values of x for which f(x) equals 1 and f(x) equals -1, we need to solve the equation f(x) = 1 and f(x) = -1, respectively.
For f(x) = 1:
1 = x^3 + 4
To solve this equation, we can subtract 4 from both sides:
1 - 4 = x^3
Simplifying:
-3 = x^3
To isolate x, we can take the cube root of both sides:
x = ∛(-3)
Using a calculator or estimating, we find that the cube root of -3 is approximately -1.4422.
So, for f(x) = 1, x is approximately -1.4422.
Now, for f(x) = -1:
-1 = x^3 + 4
To solve this equation, we can subtract 4 from both sides:
-1 - 4 = x^3
Simplifying:
-5 = x^3
Taking the cube root of both sides:
x = ∛(-5)
Using a calculator or estimating, we find that the cube root of -5 is approximately -1.7099.
So, for f(x) = -1, x is approximately -1.7099.
Based on our calculations, the values of x for which f(x) equals 1 and f(x) equals -1 are approximately -1.4422 and -1.7099, respectively. The values you mentioned (5 and 3) do not seem to be the correct solutions for this equation.