f(x)=x2(squared)-7x+10, find (a)f(0), (b) f(5), and (c) f(-2)
Put the given value in for x and calculate f(x)
I will do the middle one to show you how to do them.
f(5) = 5^2 - 7(5) + 10
f(5) = 25 -35+10
f(5) = 0
Is this right for the third one?
f(-2)=-2^2-7(-2)+10
f(-2)=-4-14+10
f(-2)=-8
Is this right if I substitute -2 for x?
f(x)=x^2-7x=10
f(-2)=-2^2-7(-2)+10
f)-2)=-4-(-14)+10
f(-2)=-8
(-2)(-2) = +4
(-7)(-2) = +14
Thank you so much I came up with an answer of 28 after some struggling.
To find the values of f(x) at specific points, you need to substitute the given values of x in the function f(x)=x^2-7x+10.
(a) To find f(0), substitute x = 0 into the function:
f(0) = (0)^2 - 7(0) + 10
= 0 - 0 + 10
= 10
Therefore, f(0) = 10.
(b) To find f(5), substitute x = 5 into the function:
f(5) = (5)^2 - 7(5) + 10
= 25 - 35 + 10
= 0
Therefore, f(5) = 0.
(c) To find f(-2), substitute x = -2 into the function:
f(-2) = (-2)^2 - 7(-2) + 10
= 4 + 14 + 10
= 28
Therefore, f(-2) = 28.
So, the answers are:
(a) f(0) = 10,
(b) f(5) = 0,
(c) f(-2) = 28.