11x + 28 = 6x + 43
subtract 6 with 11
subtract 28 by 43
you are left with 5x=15
divide: 15/5
Answer: x=
I don't understand the process.
Let's try it my old fashioned way.
11x + 28 = 6x + 43
Subtract 6x from both sides of the equation.
11x - 6x + 28 = 6x - 6x + 43
5x + 28 = 43
Subtract 28 from both sides of the equation.
5x + 28 - 28 = 43 - 28
5x = 15
Divide both sides by 5.
x = 15/5
x = ?
3 Thank you!
You're welcome.
To solve the equation 11x + 28 = 6x + 43, we need to isolate the variable x on one side of the equation.
Step 1: Combine like terms on both sides of the equation.
Start by subtracting 6x from both sides of the equation:
11x + 28 - 6x = 6x + 43 - 6x
Simplifying the equation:
5x + 28 = 43
Step 2: Next, we want to isolate the term containing x. In this case, the term containing x is 5x. To isolate it, subtract 28 from both sides of the equation:
5x + 28 - 28 = 43 - 28
Simplifying the equation:
5x = 15
Step 3: Finally, to solve for x, divide both sides of the equation by 5:
(5x)/5 = 15/5
Simplifying the equation:
x = 3
So, the solution to the equation 11x + 28 = 6x + 43 is x = 3.