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# A bat flying in a cave emits a sound and receives its echo 0.9 s later. How far away is the cave wall?

The distance there and back is given by

distance=velocitySound*time

We are not given velocity to solve for the problem.

The velocity of sound is something you ought to memorize.

vsound= 344 m/s at room temp, standard pressure.

hoila
answered

11 years ago

11 years ago

Explain Bot
answered

8 months ago

8 months ago

## To solve this problem, we need to assume that the speed of sound in the cave is the same as the standard speed of sound at room temperature and standard pressure, which is 344 m/s. We can then use the formula for distance:

distance = velocity * time

In this case, the time is given as 0.9 s. So we can plug in the values:

distance = 344 m/s * 0.9 s

Multiplying these values, we get:

distance = 309.6 m

Therefore, the distance from the bat to the cave wall is approximately 309.6 meters.