I'm not sure how to solve these problems.

Simplify

(3xsquare - 2x)divided by 15x - 10

Subtract

(2y/x-y) - 5x/4y

Solve

(27/x) = (8 - 5/x)

Simplify

(7m^7n^4/8m) divided by (9m^2n^9/5n^2)

1) 3x^2 - 2x/ 15x - 10

factorize both the numerator and denominator

x(3x-2)/ 5(3x-2)
= x/5 (the 3x-2 cancel each other

2) 2y(4y)-5x(x-y) / 4y(x-y)

The x-y cancel each other

8y^2 - 5x / 4y

4y goes in 8y^2 2 times

so the answer is
2y - 5x

3) NOT SURE ABT THAT

but i know that the 9m^2... part is gonna be multiplied to the 7m^7 part

CHECK UR WORKING OUT

Explain Bot Explain Bot answered
9 months ago

To solve the equation (27/x) = (8 - 5/x), we can start by cross-multiplying:

27/x = (8 - 5/x)
27(x) = x(8 - 5/x)

Now distribute x on the right side:

27x = 8x - 5

Combine like terms by subtracting 8x from both sides:

27x - 8x = -5

Simplify the left side:

19x = -5

Divide both sides by 19 to isolate x:

x = -5/19

4) To simplify the expression (7m^7n^4/8m) divided by (9m^2n^9/5n^2), we can simplify both the numerator and denominator separately, and then divide:

Numerator simplification:
7m^7n^4 / 8m
Divide both the coefficients and subtract the exponents of m:
7/8 * m^7/m
Simplify:
7m^6 / 8

Denominator simplification:
9m^2n^9 / 5n^2
Divide both the coefficients and subtract the exponents of m and n:
9/5 * m^2/m^0 * n^9/n^2
Since any value raised to the power of 0 is 1, we have:
9/5 * m^2 * n^7

Now, divide the numerator by the denominator:
(7m^6 / 8) / (9/5 * m^2 * n^7)

To divide fractions, we multiply the first fraction by the reciprocal of the second fraction:
(7m^6 / 8) * (5/9 * 1/m^2 * 1/n^7)

Simplify the coefficients and combine the like terms with the same bases:
35m^6 / 72mn^7