solve for the indicated varialbe
a=1/2h(B+b) solve for b
You need to clarify your equation by using more parentheses. I don't know if you mean
1/(2h) or (1/2)h at before the (B+b).
Is the B+b also supposed to be in a denominator? I will assume not.
Assuming that you mean
a = (1/2)h(B+b), then
B+b = 2a/h
Sunbtract B from both sides for the answer.
To solve for "b" in the equation a = (1/2)h(B + b), we need to isolate "b" on one side of the equation.
1. Start by distributing the (1/2)h to both terms in the parentheses:
a = (1/2)hB + (1/2)hb
2. Next, subtract (1/2)hB from both sides of the equation to move that term to the other side:
a - (1/2)hB = (1/2)hb
3. Now, we want to isolate "b" by getting rid of the fraction (1/2)h. To achieve this, we divide both sides of the equation by (1/2)h:
(a - (1/2)hB) / ((1/2)h) = b
Simplifying further:
(2(a - (1/2)hB)) / h = b
So, the solution for "b" is given by b = (2(a - (1/2)hB)) / h.