what is the graph points of (1, -3),m=-5/4 in slope-intercept form
If ifthese are linear equation then:
y=mx+b
for x=1 , y= -3 and m= -5/4
-3=(-5/4)*1+b
-3= -5/4+b
-3+5/4=b
-12/4 + 5/4=b
-7/4=b
b= -7/4
y=mx+b
y=(-5/4)x- 7/4
OR:
y=(-1/4)(5x+7)
To find the equation of the line in slope-intercept form, we can use the given information: a point on the line (1, -3) and the slope (m = -5/4).
Slope-intercept form of a linear equation is given by:
y = mx + b
Where:
m = slope of the line
b = y-intercept (the point where the line crosses the y-axis)
We have the slope (m = -5/4), so we can substitute that into the equation:
y = (-5/4)x + b
Now, we need to find the value of b, the y-intercept. We can use the given point (1, -3) to determine b. Substitute the x and y coordinates of the point into the equation and solve for b.
-3 = (-5/4)(1) + b
Multiply -5/4 by 1:
-3 = -5/4 + b
To simplify this, we need to add -5/4 and b:
-3 + 5/4 = b
To add these fractions, we need a common denominator, which is 4:
(-3 * 4)/4 + 5/4 = b
-12/4 + 5/4 = b
(-12 + 5)/4 = b
-7/4 = b
Now we have the value of b, we can substitute it back into the equation:
y = (-5/4)x + (-7/4)
Simplifying the equation gives us the final equation in slope-intercept form:
y = (-5/4)x - 7/4
Therefore, the equation of the line with the given slope and passing through the point (1, -3) in slope-intercept form is y = (-5/4)x - 7/4.