## a) The flight time of the bullet can be found using the equation t = sqrt(2h/g), where h is the vertical displacement and g is the acceleration due to gravity. In this case, the bullet lands 2 cm below the aim point, so the displacement h = -0.02 m. Plugging in the values, we get t = sqrt((2*(-0.02 m))/9.8 m/s^2), which simplifies to t â‰ˆ 0.064 s.

b) To find the velocity with which the bullet left the rifle, we can use the equation v = d/t, where v is the velocity, d is the horizontal distance traveled, and t is the flight time. In this case, the horizontal distance is given as 25 m and the flight time is approximately 0.064 s. Substituting these values, we get v = 25 m / 0.064 s â‰ˆ 390.625 m/s.

Therefore, the flight time of the bullet is approximately 0.064 seconds, and the velocity with which it left the rifle is approximately 390.625 m/s.