## Yes, you are on the right track with your calculations.

To determine the time of flight, you correctly used the equation:

t = ā(2h/g)

Where:

t is the time of flight,

h is the vertical distance the bullet fell (2 cm = 0.02 m), and

g is the acceleration due to gravity (approximately 9.8 m/s^2).

So, substituting the given values into the equation:

t = ā(2 * 0.02 m / 9.8 m/s^2)

t ā 0.0638 s

Therefore, your calculation for the flight time is correct.

Now, to determine the initial velocity of the bullet, you can use the equation of motion:

Īy = vāy * t + (1/2) * g * t^2

Since the bullet was fired horizontally, the initial vertical velocity (vāy) is zero. The equation simplifies to:

Īy = (1/2) * g * t^2

Substituting the known values:

0.02 m = (1/2) * 9.8 m/s^2 * (0.0638 s)^2

Simplifying the equation gives:

vāy ā 0.625 m/s

Therefore, your calculation for the initial velocity of the bullet is correct.

Well done! You correctly determined the time of flight and the initial velocity of the bullet.