if 25 moles of sodium phosphate are reacted with potassium hydroxide, how many grams of potassium phosphate will form?
Create a reaction:
Na3PO4 + 3 KOH --> NaOH + K3PO4
You have 25 moles of Na3PO4.....you NEED KOH
25 moles Na3PO4 x 3 mol KOH/1 mol Na3PO4
= 75 mol KOH
Convert from MOl to GRAMS
75 mol KOH x 56.106g KOH/ 1 mol KOH
To determine the number of grams of potassium phosphate that will form, we need to use the balanced chemical equation for the reaction between sodium phosphate (Na3PO4) and potassium hydroxide (KOH).
The balanced equation for this reaction is:
3 Na3PO4 + 6 KOH → 5 NaOH + K3PO4
From the equation, we can see that 3 moles of sodium phosphate react with 6 moles of potassium hydroxide to produce 1 mole of potassium phosphate.
First, we need to calculate the number of moles of potassium phosphate formed by considering the mole ratio between sodium phosphate and potassium phosphate.
Given:
- Moles of sodium phosphate (Na3PO4) = 25 moles
Using the mole ratio from the balanced equation:
1 mole of sodium phosphate (Na3PO4) reacts to form 1 mole of potassium phosphate (K3PO4)
Hence, the number of moles of potassium phosphate (K3PO4) formed would also be 25 moles.
Next, we need to convert the moles of potassium phosphate to grams. To do this, we need the molar mass of potassium phosphate (K3PO4).
The molar mass of K3PO4 can be calculated by adding up the atomic masses of each element:
Molar mass of K3PO4 = (3 * atomic mass of K) + atomic mass of P + (4 * atomic mass of O)
= (3 * 39.10 g/mol) + 30.97 g/mol + (4 * 16.00 g/mol)
= 123.30 g/mol + 30.97 g/mol + 64.00 g/mol
= 218.27 g/mol
To calculate the mass of potassium phosphate formed, we can use the equation:
Mass = Number of moles * Molar mass
Mass of potassium phosphate (K3PO4) = 25 moles * 218.27 g/mol
= 5456.75 g
Therefore, 25 moles of sodium phosphate will react to form approximately 5456.75 grams of potassium phosphate.