A mixture of KCI and KClO3 weighing 1.80g was heated. The dry O2 generated occupied 140ml at STP. What percent of the original mixture was KCl03?

1 answer

1. You know 1 mol oxygen (32.0 grams) occupies 22.4L at STP. Convert 140 mL to grams, then,
   %oxygen = (mass oxygen/mass original sample)*100 = ??%

   Answer ID
   539787

   Created
   April 30, 2011 11:10pm UTC

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   https://questions.llc/answers/539787