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The mass of calcium hydrogen carbonate that would be found in 52.0L of hard water in a bathtub is _______________ g.

The amount concentration of calcium hydrogen carbonate in the hard water is __________mmol/L

Question ID
539699

Created
April 30, 2011 9:33pm UTC

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1

URL
https://questions.llc/questions/539699

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3

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1833

3 answers

  1. You don't provide enough information to solve this problem.

    Answer ID
    539705

    Created
    April 30, 2011 9:42pm UTC

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    0

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  2. 200 ppm Ca(HCO3)2 is 200 mg/L. In 52.0 L there will be 200 mg/L x 52.0 L = ?? mg. Convert that to grams.

    200 ppm is 200 mg/L which is 0.200g/L. Convert 0.200 g Ca(HCO3)2 to moles (moles = grams/molar mass), then to mmoles.

    Answer ID
    539739

    Created
    April 30, 2011 10:28pm UTC

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    1

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  3. I do not like

    Answer ID
    1869228

    Created
    May 14, 2019 3:27am UTC

    Rating
    3

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