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Logarithmic differentiation

f(x)=(2x-1)^-2 (x+3)^4 at x=1

f'(x)= -2*2/2x+1 + 4*1/x+3 [(2x-1)^-2)(x+3)^4 and then I plug in 1.

I am having trouble getting an answer when I plug in 1.

Question ID
539652

Created
April 30, 2011 7:49pm UTC

Rating
0

URL
https://questions.llc/questions/539652

Answers
2

Views
328

2 answers

  1. Can you re-write I think there is something missing.

    Answer ID
    539683

    Created
    April 30, 2011 9:06pm UTC

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    0

    URL

  2. You lost me totally

    d/dx (a * b) = a db/dx + b da/dx

    f= (2x-1)^-2 * (x+3)^4

    f' = [(2x-1)^-2][4(x+3)^3]
    + (x+3)^4 (-2(2x-1)^-3 (2)]

    at x = 1
    f' = [(2-1)^-2][4(4)^3]
    + (4)^4 (-2(1)^-3 (2)]
    which is
    f' = [1][4^4]
    + (4)^4 (1/4]
    or
    4^4+4^3 = 4^3(5)= 320
    check my arithmetic !

    Answer ID
    539690

    Created
    April 30, 2011 9:16pm UTC

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    0

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