Is that supposed to be (4, -ƒÎ/6)?
If so, you would use this formula:
x = rcosӨ
y = rsinӨ
x = 4cos(-ƒÎ/6)
y = 4sin(-ƒÎ/6)
-ƒÎ/6 on the unit circle is the same as 11ƒÎ/6. The cosine (or x-value) for this angle is �ã3/2, and the sine (or y-value) for this angle is -1/2.
x = 4(�ã3/2)
y = 4(-1/2)
x = 2�ã3
y = -2
Your answer is:
(2�ã3, -2)
