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1) where is the function

f(x)= 5 / (2x-4)^3 increasing.

I know the answer is for all of x but I do not know how to get this. I know that you can write the equation as 5(2x-4)^-3

2) Let a, b, and c be fixed with a>0 and let f(x)=ax^2 + bx + c. Which of the following properties is true of the graph of f(x)?

a)f(x) has either a relative max or inflection point

b) f(x) is always concave up

c)f(x) has one inflection point
d) f(x) has one relative max
e) none of these

I know that the anwer is that f(x) is always concave up but I am not sure why.

Thank you for your help!!

Question ID
539534

Created
April 30, 2011 3:59pm UTC

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https://questions.llc/questions/539534

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1 answer

  1. What you know on 1 is wrong. If the denominator is increasing, the function is decreasing. But when 2x-4 is decreasing, thenf is increasing. 2x-4 is decreasing when 2x-4<1 or x<2

    check that.

    2.

    f=ax^2+bx+c
    f'=2ax+b
    f"=2a, but a>o, so f" is always +

    Answer ID
    539539

    Created
    April 30, 2011 4:19pm UTC

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