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A ship is 90 miles south and 20 miles east of port. The captain wants to travel directly to port. What bearing should be taken?

Question ID
538972

Created
April 29, 2011 2:27am UTC

Rating
0

URL
https://questions.llc/questions/538972

Answers
4

Views
3663

4 answers

  1. "90 miles south and 20 miles east of port"
    means the direction along which the ship must sail is:
    x=-90, y=20
    angle = atan(20,-90) = 180° - 12°-31'-44"
    = 167°-28'-16" (in trigonometry notation).

    To convert trigonometry notation to bearing, subtract angle from 90° or 450° if the angle exceeds 90°.

    Bearing (clockwise from north)
    = 450° - 167°-28'-46"
    = 282°-31'-44"

    Answer ID
    539028

    Created
    April 29, 2011 3:51am UTC

    Rating
    -11

    URL

  2. uiuhi

    Answer ID
    1521604

    Created
    January 23, 2017 4:57pm UTC

    Rating
    -4

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  3. hi but

    Answer ID
    1521605

    Created
    January 23, 2017 4:58pm UTC

    Rating
    -2

    URL

  4. A ship leaves port A and travels north for 47km and arrives at port B.It then travels east to port C which lies 35% of port A.How far is port C from port B? Draw a diagram to help you calculate.

    Answer ID
    2014878

    Created
    May 10, 2020 10:05am UTC

    Rating
    0

    URL

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