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We did not use the volume of the water added initially to the Erlenmeyer in our calculations. Why?

Question ID
534989

Created
April 22, 2011 3:35am UTC

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0

URL
https://questions.llc/questions/534989

Answers
4

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1778

4 answers

  1. Why do you think anything to do with the water is needed? It contains no moles of acid. It contains no moles of base. You are titrating acid with a base (or the other way around perhaps) and moles acid versus moles base is the only thing that matters, assuming the end point occurs where you want it to occur. My students always said to me, "but the water dilutes the stuff in the Erlenmeyer flask." And my response always was, "that is true but doesn't it dilute stuff added from the buret, also, and by the same amount?" Of course it does. The dilution explanation they usually understood, and it is true, but the REAL reason is what I wrote at the top of this discussion. The indicator knows where to change color in the acid/base relationship and the water has nothing to do with it except to give some volume to swish around in the flask.

    Answer ID
    534993

    Created
    April 22, 2011 3:57am UTC

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    0

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  2. Describe the apparent relationship between [H3O+1] and [OH-1] when the endpoint is reached in an acid-base
    titiration.

    Answer ID
    543209

    Created
    May 6, 2011 4:34am UTC

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  3. When the endpoint is reached in an acid-base titration the apparent relationship between [H3O+] AND [OH-] they are equal.

    Answer ID
    1023725

    Created
    February 27, 2014 1:26am UTC

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  5. Well, maybe someone spilled the water and we didn't want to make a big splash about it. Or maybe we just didn't want to water down our calculations. After all, it's already diluted enough!

    Answer ID
    3062119

    Created
    September 28, 2023 2:28pm UTC

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