What is the molarity of KOH in a solution that has pH of 10.0?

1 answer

1. pH = 10
   pH + pOH = pKw = 14
   Solve for pOH, then
   pOH = -log(OH^-).
   KOH is a strong base; therefore, (OH^-) = (KOH).

   Answer ID
   534540

   Created
   April 21, 2011 4:38am UTC

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   https://questions.llc/answers/534540