work= PE1-PE= q1V1-q2V2=.25 (-30)=-7.5J
PE change = - work done
A work of 30 joules is done transferring 5mili Coulombs of charge from a point B to a point A in an electric field field . Find the potential difference between A and B
A proton is located at a distance of 0.430 m from a point charge of +8.30 µC. The repulsive electric force moves the proton until it is at a distance of 1.55 m from the charge. Suppose that the electric potential energy lost by the system is carried off
A +3.0 nC charge is at x=0 cm and a -1.0 nC charge is at x=4 cm. At what point or points on the x-axis is the electric potential zero?
1. A positively charged test object is moving toward the positive source charge in an electric field. What happens next??? A. its potential energy decreases. B. Its potential energy increases. C. Its potential energy stays the same. D. Its potential energy
moving a charge from point a,where the potential is 300v, to point b,where the potential is 150v takes 4.5x 10-4 J ofwork. What is the value of the charge?
The electric potential in a certain region is V = a x2 + b x + c, where a = 14 V/m2, b = −19 V/m, and c = 61 V. Determine the position where the electric field is zero. Answer in units of m Please help!
A point charge has an excess of 5.0 × 1012 electrons. What would be the electric potential at a distance of 0.50 m from the charge? (e = 1.6 × 10-19 C)
A point charge (m = 1.0 g) at the end of an insulating string of length L = 51 cm (Fig. 16-66) is observed to be in equilibrium in a uniform horizontal electric field of E = 9200 N/C, when the pendulum's position is as shown in Fig. 16-66, with the charge
A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved? Show work. (µC = 1.0 × 10–6 Vq=energy so delta V must be 10
If the total positive charge is Q = 1.62×10−6C , what is the magnitude of the electric field caused by this charge at point P, a distance d = 1.53m from the charge? (Figure 1) Enter your answer numerically in newtons per coulomb.
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