F * d = q * V
V = F * d / q
= .053 * .3 /36*10^-6
= 5.3 * 10^-2 * 3 * 10^-1 *10^6/36
= .442 * 10^3
= 442 volts
V = F * d / q
= .053 * .3 /36*10^-6
= 5.3 * 10^-2 * 3 * 10^-1 *10^6/36
= .442 * 10^3
= 442 volts
To find the electric potential difference (also known as voltage), we can use the formula:
V = W/q
Where V is the electric potential difference, W is the work done by the electric field, and q is the charge.
Now, the work done, W, is given by the formula:
W = F * d
Where F is the force and d is the distance.
So, let's plug in the values we have! We have a force of 0.053 N and a distance of 30 cm (which we'll convert to meters by dividing by 100).
W = 0.053 N * (30 cm / 100) m = 0.0159 N∙m
Next, we need to convert the charge of 36 µC (that's microcoulombs) to coulombs. Remember, 1 µC = 10^(-6) C.
q = 36 µC * (1 C / 10^(-6) µC) = 0.000036 C
Now we'll plug these values into the formula for electric potential difference:
V = (0.0159 N∙m) / (0.000036 C)
And after some number crunching, we get:
V ≈ 441.67 volts
So, the electric potential difference between the two points is approximately 441.67 volts. Shocking, isn't it? Keep those electrons flowing smoothly!
ΔV = F * d
Where:
ΔV is the electric potential difference
F is the force applied
d is the distance over which the force is applied
Given:
Force (F) = 0.053 N
Charge (q) = 36 µC = 36 * 10^-6 C
Distance (d) = 30 cm = 30 * 10^-2 m
First, let's convert the charge to Coulombs:
q = 36 * 10^-6 C
Now, we can calculate the electric potential difference:
ΔV = F * d
= q * d
Substituting the given values:
ΔV = (36 * 10^-6 C) * (30 * 10^-2 m)
= (36 * 10^-6 C) * (0.3 m)
= 10.8 * 10^-6 C * m
Simplifying, we get:
ΔV = 10.8 * 10^-6 C * m
= 10.8 * 10^-6 V * m
= 10.8 µV * m
Therefore, the electric potential difference between the two points is 10.8 µV * m.
Electric Potential Difference (V) = Work done (W) / Charge (Q)
First, let's find the work done (W) using the formula:
W = Force (F) * Distance (d)
Given:
Force (F) = 0.053 N
Distance (d) = 30 cm = 0.30 m
W = 0.053 N * 0.30 m
W = 0.0159 J
Next, we need to find the charge (Q). We are given that a force of 0.053 N is required to move a charge of 36 µC (microcoulombs). To convert microcoulombs to coulombs, we divide by 1,000,000:
Charge (Q) = 36 µC / 1,000,000
Q = 0.000036 C
Now we can substitute the values into the formula to find the electric potential difference (V):
V = W / Q
V = 0.0159 J / 0.000036 C
Calculating this value:
V ≈ 441.67 V
Therefore, the size of the electric potential difference between the two points is approximately 441.67 volts (V).