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A salesperson has found that the probability of making various numbers of sales per day is presented in the following table. Calculate the expected number of sales per day and the standard deviation of the number of sales.

Number of sales(Probability)
1(0.05) 2(0.16) 3(0.20) 4(0.25) 5(0.18) 6(0.10) 7(0.04) 8(0.02)

Question ID
528237

Created
April 9, 2011 5:41pm UTC

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0

URL
https://questions.llc/questions/528237

Answers
2

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2023

2 answers

  1. Find the mean first = sum of scores/number of scores

    Sum of scores = (.05) + 2(.16)... + 8(.02) = ?

    Number of scores = 1 + 2 + 3... + 8

    Subtract each of the scores (.05, .16, .16, .2, .2, .2....) from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.

    Standard deviation = square root of variance

    I'll let you do the calculations.

    Answer ID
    528525

    Created
    April 10, 2011 4:15pm UTC

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  2. μ = ∑[x * P (x)]
    μ = [(0*0.06) + (1*0.25) + (2*0.37) + (3*0.25) + (4*0.06)]
    μ = 0 + 0.25 + 0.74 + 0.75 + 0.24
    μ = 1.98

    σ2 = ∑[x2 * P(x)] – μ2
    σ2 = [(02*0.06) + (12*0.25) + (22*0.37) + (32*0.25) + (42*0.06)] – 1.98
    σ2 = [(0*0.06)+(1*0.25)+ (4*0.37) + (9*0.25) + (16*0.06)] – 3.92
    σ2 = [0 + 0.25 + 1.48 + 2.25 + 0.96] – 3.92
    σ2 = 4.94 - 3.92
    σ2 = 1.02

    σ = √σ2
    σ = √1.02
    σ = 1.009

    Answer ID
    2346080

    Created
    March 22, 2022 10:14am UTC

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