The sound of heavy automobile traffic, heard at a certain distance, has a sound level of about 75 dB. What is the intensity of the noise there? answer in W/m^2.
seriously no has yet answered.ugh.
To determine the intensity (I) of the noise at a certain distance, given the sound level (L) in decibels (dB), you can use the formula:
I = 10^((L - 10log10(I0))/10)
where I0 represents the reference intensity level, which is 10^-12 W/m^2.
In this case, the sound level (L) is 75 dB. Thus, we can substitute the values into the formula:
I = 10^((75 - 10log10(10^-12))/10)
First, let's solve the logarithm component:
log10(10^-12) = -12 log10(10) = -12 * 1 = -12
Substitute the value back into the formula:
I = 10^((75 - 10 * (-12))/10)
= 10^((75 + 120)/10)
= 10^(195/10)
Now, calculate 195/10:
I = 10^19.5
Finally, calculate the result:
I ≈ 316227.766 W/m^2
Therefore, the intensity of the noise at that distance is approximately 316,227.766 W/m^2.