A sample of 36 females is taken. What is the probability that the mean height of these women is shorter than 64 inches if we know the height for all American females is N(63,3^2)?

1 answer

1. Z = (mean1 - mean2)/standard error (SE) of difference between means
   
   SEdiff = √(SEmean1^2 + SEmean2^2)
   
   SEm = SD/√(n-1) or just √n
   
   If only one SD is provided, you can use just that to determine SEdiff.
   
   Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.
   
   For the random woman:
   
   Z = (score-mean)/SD

   Answer ID
   525221

   Created
   April 4, 2011 2:47pm UTC

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   https://questions.llc/answers/525221