How many milliters of 0.500 M magnesium nitrate can be produced from the reaction of 35.5 grams of magnesium bromide.

1 answer

1. moles MgBr2 = grams/molar mass = ??
   1 mole MgBr2 = 1 mole Mg(NO3)2
   M Mg(NO3)2 = moles/L soln
   Solve for L and convert to mL.

   Answer ID
   524964

   Created
   April 4, 2011 12:19am UTC

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   https://questions.llc/answers/524964