find x? I have no idea how to do this

Question ID 524147

Created April 2, 2011 3:20am UTC

Rating 0

URL https://questions.llc/questions/524147

Answers 2

Views 223

(e^x)^-2=1/(e^x)^2 (e^x)^-2*(e^x)^2*e^x=[1/(e^x)^2]*[(e^x)^2]*e^x=1/e^2 [1/(e^x)^2]*[(e^x)^2]=1 1*e^x=1/e^2 e^x=e^-2 ln(e^x)=ln(e^-2) ln(e^x)=x ln(e^-2)= -2 x= -2

Answer ID 524160

Created April 2, 2011 4:54am UTC

URL https://questions.llc/answers/524160

Thank You so much!!

Answer ID 524209

Created April 2, 2011 2:52pm UTC

URL https://questions.llc/answers/524209

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