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If (e^x)^-2 X (e^x)^2 X e^x = 1/e^2

find x?

I have no idea how to do this

Question ID
524147

Created
April 2, 2011 3:20am UTC

Rating
0

URL
https://questions.llc/questions/524147

Answers
2

Views
223

2 answers

  1. (e^x)^-2=1/(e^x)^2

    (e^x)^-2*(e^x)^2*e^x=[1/(e^x)^2]*[(e^x)^2]*e^x=1/e^2

    [1/(e^x)^2]*[(e^x)^2]=1

    1*e^x=1/e^2

    e^x=e^-2

    ln(e^x)=ln(e^-2)

    ln(e^x)=x

    ln(e^-2)= -2

    x= -2

    Answer ID
    524160

    Created
    April 2, 2011 4:54am UTC

    Rating
    0

    URL

  2. Thank You so much!!

    Answer ID
    524209

    Created
    April 2, 2011 2:52pm UTC

    Rating
    0

    URL