April 1, 2011 5:04am UTC
Let the shortest leg length be a.
Area = (a)*(3a/2)*(1/2) = (3/4)a^2 = 12
a^2 = 16
a = 4 and the other leg (which we'll call b) must be 6.
Use the Pythagorean theorem for the hypotenuse, c.
c^2 = a^2 + b^2
c = sqrt(52) = 7.2111 inch
April 1, 2011 11:17am UTC
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