with the equation
q=-p^2+33p+9 (18 less than or equal to p less than or equal to 28)
how do you determine the price to obtain the largest revenue?
It's not factorable, so use a graphic calculator. Observe the graph. (Where is it highest?) Then, type that x-coordinate into the table of your graph to get the largest revenue (y).
i don't do anything with take a derivative?
Oh yea. You have to find the derivate and then follow those steps. Good eye. :)
derivative*
what about the inequality?
i substituted the q with the equation with r=p*q but i don't kno what to do after that
Don't worry about the inequality. To begin, simply find the derivative of:
q=-p^2+33p+9
(Use the power rule.)
ok
q'=-2p+33
Are you sure that q=-p^2+33p+9 isn't our derivative? That makes much more sense.
(With our current derivative, it's not profitable at all. We're losing money.)