At a pressure of 405 kPa, the volume of a gas is 6.00 cm3. Assuming the
temperature remains constant, at what pressure will the new volume be 4.00
cm3?
Use (P1/T1) = (P2/T2)
300k
To find the new pressure, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when temperature remains constant.
Boyle's Law can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given:
P1 = 405 kPa
V1 = 6.00 cm³
V2 = 4.00 cm³
Using Boyle's Law, we can rearrange the equation to solve for P2:
P2 = (P1 * V1) / V2
Plugging in the values:
P2 = (405 kPa * 6.00 cm³) / 4.00 cm³
Calculating:
P2 = 2430 kPa / 4.00 cm³
P2 = 607.5 kPa
Therefore, at a new volume of 4.00 cm³, the pressure of the gas will be approximately 607.5 kPa.
To solve this problem, we can use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when the temperature remains constant.
Boyle's Law formula can be written as:
P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
We are given:
P1 = 405 kPa
V1 = 6.00 cm^3
V2 = 4.00 cm^3
Let's plug these values into the formula and solve for P2:
P1 * V1 = P2 * V2
405 kPa * 6.00 cm^3 = P2 * 4.00 cm^3
Now, we can solve for P2:
P2 = (405 kPa * 6.00 cm^3) / 4.00 cm^3
P2 = 2430 kPa / 4.00 cm^3
P2 = 607.5 kPa
Therefore, at a constant temperature, the new pressure will be 607.5 kPa when the volume becomes 4.00 cm^3.