assuming a peak flow velocity of 3 m/s determine culvert diameter if peak flow rate will 9790 cubic metres per second
To determine the culvert diameter, we can use the equation relating flow rate, velocity, and cross-sectional area of flow.
The equation is:
Flow Rate = Cross-sectional Area * Velocity
Given:
Peak flow velocity = 3 m/s
Peak flow rate = 9790 cubic meters per second
We can rearrange the equation to solve for the cross-sectional area:
Cross-sectional Area = Flow Rate / Velocity
Now, let's substitute the given values:
Cross-sectional Area = 9790 cubic meters per second / 3 m/s
Cross-sectional Area = 3263.33 square meters
The area of a circle is given by the formula:
Area = π * (radius)^2
Since we are dealing with a culvert that is a circular cross-section, we can find the radius by rearranging the formula:
radius = sqrt(Area / π)
Substituting the calculated cross-sectional area:
radius = sqrt(3263.33 square meters / π)
radius ≈ 32.19 meters
Finally, the diameter of the culvert is twice the radius:
diameter ≈ 2 * 32.19 meters
diameter ≈ 64.38 meters
Therefore, the culvert diameter, assuming a peak flow velocity of 3 m/s and a peak flow rate of 9790 cubic meters per second, would be approximately 64.38 meters.