8(4u-1)-12u=11(2u-6)
32u-8-12u=22u-66
-12
20u-8=22u-66
-20u
-8=2u-66
-8
2u=74
u=37
i kno 1 messed up but idk where
all wrong
ok then how do i do it?
cuz i kno i didn't get it all rong
u meeased up in ur face
To solve the equation 8(4u-1)-12u=11(2u-6), you first need to apply the distributive property on both sides of the equation:
8 * 4u - 8 * 1 - 12u = 11 * 2u - 11 * 6
Next, simplify both sides of the equation:
32u - 8 - 12u = 22u - 66
Combine like terms on both sides of the equation:
(32u - 12u) - 8 = 22u - 66
20u - 8 = 22u - 66
Now, isolate the variable u by moving the terms involving u to one side of the equation and the constants to the other side. You can do this by subtracting 20u from both sides:
20u - 20u - 8 = 22u - 20u - 66
-8 = 2u - 66
Next, add 66 to both sides of the equation to get rid of the -66:
-8 + 66 = 2u - 66 + 66
58 = 2u
Finally, divide both sides of the equation by 2 to solve for u:
58/2 = 2u/2
29 = u
So, the solution to the equation is u = 29.
It seems there was an error in your calculations where you substituted the value of u back into the equation. The correct solution is u = 29, not u = 37.