Describe the end behavior for the graph of y= 12x^6 + 4x^4 - x^3 + 6x +1
if you graph x from - 1 to 1
the graph looks like a U
not much help, but you really need to plot yourself
from -0.8 to 0.6 the graph dips in a little u then rises steadily up, up and up to the right
To describe the end behavior of the graph of the equation y = 12x^6 + 4x^4 - x^3 + 6x + 1, we need to look at the exponents of the highest degree term and determine whether it is positive or negative.
In this case, the highest degree term is 12x^6. Since the exponent 6 is even, the end behavior can be described as follows:
As x approaches negative infinity, the value of y approaches positive infinity. This is because for negative values of x, the positive coefficients of the terms dominate the equation.
As x approaches positive infinity, the value of y also approaches positive infinity. This is because for positive values of x, the positive coefficients of the terms dominate the equation.
Therefore, the end behavior of the graph of y = 12x^6 + 4x^4 - x^3 + 6x + 1 is that it goes towards positive infinity both as x approaches negative infinity and as x approaches positive infinity.