23. A 32.3 L sample of a gas at 305oC and 1.20 atm is to be cooled at constant pressure until its volume becomes 28.4L. What will be the new gas temperature?
Tf = Vf*Ti/Vi
Tf =28.4L x (305+273)K / 32.3L
= (28.4)(578)K / 32.3
= 16415.2/32.3
Tf = 508K
I got this one wrong on a test please let me know what I'm doing wrong???
I get 508.2 K which rounds to 508 K. I don't see anything wrong with what you've done. Perhaps the answer was supposed to be in celsius.
In the formula you used, Tf = Vf * Ti / Vi, you correctly substituted the values for Vf, Ti, and Vi. However, it seems like you made a mistake in your calculation.
Let's go through it step by step:
Tf = (28.4 L * (305 °C + 273.15 K)) / 32.3 L
First, we need to convert the initial temperature from Celsius to Kelvin by adding 273.15 K:
Tf = (28.4 L * (578.15 K)) / 32.3 L
Now, we can simplify the equation:
Tf = (16365.26 K) / 32.3
Calculating this division, we get:
Tf ≈ 507.105 K
So, the correct answer is approximately 507.105 K, rather than 508 K. It seems like you made a small rounding error in your final calculation.
Remember to be cautious with rounding and make sure to use accurate values for the temperature conversion.