How many grams of chloride are present in 1.00 liter of a 1.5 M solution of CaCl2?
1.5M? that means 3M of chloride ions.
gramschlorideions=3M*1liter*massCl-
this is a stupid question but is it 3M because of the Cl2 and not just Cl?
yes.
To find the number of grams of chloride present in the 1.00 liter solution of CaCl2, you need to first calculate the number of moles of CaCl2 and then the moles of chloride (Cl-) ions. Finally, you can convert the moles of chloride to grams using the molar mass of chloride.
Here's how you can calculate it step by step:
1. Calculate the number of moles of CaCl2:
Molarity (M) = Number of moles (mol) / Volume (L)
Rearrange the formula to solve for moles:
Number of moles (mol) = Molarity (M) * Volume (L)
In this case, the molarity is given as 1.5 M, and the volume is given as 1.00 L:
Number of moles of CaCl2 = 1.5 M * 1.00 L = 1.5 mol CaCl2
2. Calculate the moles of chloride ions (Cl-):
Since each formula unit of CaCl2 produces 2 chloride ions, you need to multiply the number of moles of CaCl2 by 2:
Number of moles of Cl- ions = 2 * 1.5 mol CaCl2 = 3.0 mol Cl-
3. Convert moles of chloride to grams:
To convert moles of chloride to grams, multiply by the molar mass of chloride (Cl-), which is approximately 35.45 g/mol:
Grams of chloride = 3.0 mol Cl- * 35.45 g/mol = 106.35 g
Therefore, there are 106.35 grams of chloride present in 1.00 liter of a 1.5 M solution of CaCl2.