An Antique dealer visited three shops. she spend $25 at the first shop. At the second shop, she spent half of her remaining money. At the third shop, she spent one third of her remaining money and had $60 left. How much money did the dealer have orginally?
25
1/2
1/3
60 left
+25
____
85
+1/2
____
122.50
+1/3
______
163.33
not sure if it is right but i sure if highley possoble:) double check it.
To find out how much money the dealer originally had, let's work through the given information step by step.
1. The dealer spends $25 at the first shop, which means she has spent $25 and has some money remaining.
2. At the second shop, she spends half of her remaining money. This means she spends (1/2) * (remaining money).
3. After spending at the second shop, the dealer has (remaining money) - (1/2) * (remaining money) left.
4. At the third shop, she spends one third of her remaining money and has $60 left. So, she spent (1/3) * (remaining money) at the third shop.
5. We also know that after spending at the third shop, the dealer had $60 left. Therefore, we can set up the equation:
(remaining money) - (1/3) * (remaining money) = $60
To solve this equation and find the remaining money, we can simplify it:
(2/3) * (remaining money) = $60
Dividing both sides of the equation by (2/3):
(remaining money) = $60 / (2/3)
= $60 * (3/2)
= $90
Now that we know the remaining money is $90, we can find the dealer's original amount:
(original money) = (remaining money) + (amount spent at the third shop)
= $90 + (1/3) * ($90)
= $90 + $30
= $120
Therefore, the dealer originally had $120.