a) C(25,8)=
b) C(17,2)=
c) C(15,15)=
d) multiply the above results
e) prob = C(8,3)/C(25,3) =
Assume that all employees will work on exactly one team. Also, each employee has the same qualifications/skills, so any employee can serve on any team.
The number of employees on each project are as follows: 8 on Team A, 2 on Team B, and 15 on Team C.
(a) How many ways can Team A be selected from the available employees?
(b) Then, how many ways can Team B be selected from the remaining available employees?
(c) Then, how many ways can Team C be selected from the remaining available employees?
(d) Then, how many ways can all teams be selected?
(e) What is the probability that three workers randomly selected from all employees will all be from team A?
b) C(17,2)=
c) C(15,15)=
d) multiply the above results
e) prob = C(8,3)/C(25,3) =
Responses
400 randomly chosen employees from the list of all employees
all 624 female employees in the company
a group with one member from each department
all employees who have worked in the company for 5 years or more
Responses
100 lamps on each floor chosen randomly
100 lamps on each floor chosen randomly
400 lamps on the first 10 floors
400 lamps on the first 10 floors
all lamps from the rooms with king-sized beds
all lamps from the rooms with king-sized beds
all lamps in booked rooms
If 3 out of 80 surveyed patrons borrowed novels, we can set up a proportion:
3/80 = x/345
where x is the number of patrons who borrow novels out of the total 345 patrons.
Solving for x, we get:
x = 3/80 * 345
x = 12.94
Rounding to the nearest whole number, approximately 13 patrons out of the 345 total patrons borrow novels when they visit the library.
3/80 = x/345
x = (3/80)*345
x = 12.9375
Rounding to the nearest whole number, there are approximately 13-14 patrons out of 345 who borrow novels.
Group A:18, 20, 46, 34, 58, 31, 41
Group B: 15, 21, 32, 42, 29, 57, 39. The table shows the times, in minutes, spent shopping by two different groups. First find the mean times each group spent shopping. Then determine the difference in the mean times. Round your answers to one decimal place.
The mean time Group A spent shopping is _minutes.
The mean time Group B spent shopping is _minutes.
The mean times Group A and Group B spent shopping differ by _minutes.
Mean = (18 + 20 + 46 + 34 + 58 + 31 + 41) / 7
Mean = 248 / 7
Mean ≈ 35.43 minutes
The mean time Group B spent shopping:
Mean = (15 + 21 + 32 + 42 + 29 + 57 + 39) / 7
Mean = 235 / 7
Mean ≈ 33.57 minutes
The difference in means:
35.43 - 33.57 ≈ 1.9
The mean times Group A and Group B spent shopping differ by approximately 1.9 minutes.
{11, 15, 16, 8, 12, 14}
{8, 20, 13, 14, 12, 9}
{1, 6, 15, 7, 15, 18, 14}
{1, 10, 8, 29, 14, 17, 3}
{8, 11, 12, 14, 15, 16}
{8, 9, 12, 13, 14, 20}
{1, 6, 7, 14, 15, 15, 18}
{1, 3, 8, 10, 14, 17, 29}
The median is the middle value in the set of data when they are arranged in order. If there are two middle values, then the median is the average of those two values.
For the first data set, the median is 13.
For the second data set, the median is 12.5.
For the third data set, the median is 14.
For the fourth data set, the median is 10.
Therefore, the data set with the highest median is the third data set: {1, 6, 15, 7, 15, 18, 14}.
Therefore, we have:
For the first data set, the median is 13.
For the second data set, the median is 11.5.
For the third data set, the median is 15.
For the fourth data set, the median is 10.
Hence, the answer is the third data set {1, 6, 15, 7, 15, 18, 14}.
Value per House ~ Number of Houses
$150,000 2
$220,000 4
$490,000 3
$540,000 2
$800,000 5
$975,000 2
The values of several houses on Mango Street are displayed on the table. What is the median value of these houses?
$150,000, $220,000, $490,000, $540,000, $800,000, $800,000, $800,000, $800,000, $800,000, $975,000, $975,000
The median is the middle value of the data set. We have 11 values, so the median is the value that falls in the middle when the values are arranged in order:
$150,000, $220,000, $490,000, $540,000, $800,000, $800,000, $800,000, $800,000, $800,000, $975,000, $975,000
The median is the average of the two middle values:
Median = ($800,000 + $800,000) / 2
Median = $800,000
Therefore, the median value of these houses is $800,000.