What is the mole of oxalic acid?
Equation:H2C2O4 + 2NaOH---> Na2C2O4 + 2H2O
*Moles of oxalic acid dihydrate is 0.032 mole.
* Molarity of oxalic acid solution is 0.128 M oxalic acid solution.
* Initial volume of Oxalic acid is 19.8 ml
and Final volume is 23.0 ml
To determine the number of moles of oxalic acid, we can use the provided information about the moles of oxalic acid dihydrate and the molarity of the oxalic acid solution.
1. Start by converting the initial and final volume of oxalic acid solution from milliliters to liters:
Initial volume = 19.8 ml = 19.8/1000 = 0.0198 L
Final volume = 23.0 ml = 23.0/1000 = 0.0230 L
2. Calculate the change in volume of the oxalic acid solution:
Change in volume = Final volume - Initial volume
= 0.0230 L - 0.0198 L
= 0.0032 L
3. Use the definition of molarity to calculate the number of moles of oxalic acid in the solution:
Molarity (M) = Moles of solute / Volume of solution (in L)
Rearrange the equation to solve for moles of solute:
Moles of solute = Molarity x Volume of solution
Moles of oxalic acid = 0.128 mol/L x 0.0032 L
= 0.0004096 mol
Hence, the number of moles of oxalic acid in the given solution is approximately 0.0004096 mole.