#1.) A solar photovoltaic panel has an area of 3 m^2. The panel's maximum power output is 595 W @ 1100 W/m^2.
a) What is its efficiency?
b) If the panel receives 1300 W/m^2 of irradiance, what is its new power output?
#2.) A solar voltaic module has a maximum output of 200 W @ 1100 W/m^2 when connected to a 2 ohm resistor. What is the maximum voltage and current?
3300 Watts if 100% efficient
595/3300 = .18 so 18%
13/11 * 595 = 703 Watts
2.
200 = V i = i^2 R
i^2 =200/2 =100
i = 10 amps
so
V = i R = 10*2 = 20 volts
To answer these questions, we need to understand the basic formulas and concepts related to solar photovoltaic panels.
#1.)
a) Efficiency is defined as the ratio of the actual power output to the maximum power output. The formula for efficiency is:
Efficiency = (Actual Power Output / Maximum Power Output) * 100
Given:
Maximum Power Output = 595 W
Area of the panel = 3 m^2
Solar irradiance = 1100 W/m^2
To find the actual power output, we can use the formula:
Actual Power Output = Maximum Power Output * (Solar Irradiance / 1000) * Area
Substituting the given values:
Actual Power Output = 595 W * (1100 W/m^2 / 1000) * 3 m^2
Actual Power Output = 1827 W
Now we can calculate the efficiency:
Efficiency = (1827 W / 595 W) * 100
Efficiency = 306.3%
So, the efficiency of the solar photovoltaic panel is approximately 306.3%.
b) To find the new power output when the panel receives 1300 W/m^2 of irradiance, we can use the same formula as before:
Actual Power Output = Maximum Power Output * (Solar Irradiance / 1000) * Area
Substituting the given values:
Actual Power Output = 595 W * (1300 W/m^2 / 1000) * 3 m^2
Actual Power Output = 2281.5 W
Therefore, the new power output of the panel, when it receives 1300 W/m^2 of irradiance, is approximately 2281.5 W.
#2.)
To find the maximum voltage and current of a solar voltaic module, we need to use Ohm's Law. Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage across the two points. The formula for Ohm's Law is:
V = I * R
where V is the voltage, I is the current, and R is the resistance.
Given:
Maximum Power Output = 200 W
Solar Irradiance = 1100 W/m^2
Resistance = 2 ohms
To find the maximum current, we can rearrange Ohm's Law:
I = V / R
Substituting the given values:
I = √(P / R)
I = √(200 W / 2 ohms)
I = √(100) A
I = 10 A
Therefore, the maximum current of the solar voltaic module is 10 A.
To find the maximum voltage, we can rearrange Ohm's Law:
V = I * R
Substituting the given values:
V = 10 A * 2 ohms
V = 20 V
Therefore, the maximum voltage of the solar voltaic module is 20 V.