a 50.0 ml sample of a 15% (m/v) solution of H2SO4 is added to water to give a final volume of 250.0 ml. What would the final concentration be?
I assume the subject is chemistry. Just trying to help you get answers more quickly. :-)
Quantity of H2SO4 did not change, the volume is increased by a factor of 5.
The concentration is therefore
15%/5=3% (m/v) assuming the volumes are measured at the same temperature.
To find the final concentration of the solution, we need to use the equation:
C1V1 = C2V2
Where:
C1 = Initial concentration
V1 = Initial volume
C2 = Final concentration
V2 = Final volume
In this case, we have:
C1 = 15% (m/v) solution of H2SO4
V1 = 50.0 ml
V2 = 250.0 ml
Step 1: Convert the percentage to a decimal.
15% = 0.15
Step 2: Substitute the values into the equation.
(0.15)(50.0 ml) = C2(250.0 ml)
Step 3: Solve for C2.
C2 = (0.15)(50.0 ml) / (250.0 ml)
C2 = 0.03 m/v
Therefore, the final concentration of the solution after adding water is 0.03 m/v.