how would i find the value of r if 5(r-1)=2(r-4)-6
5r-5=2r-8-6
add 5 to each side
subtract 2r from each side.
so would r=-3
correct. Go to the head of the class.
5r-5=2r-8-6
5r-2r= -8-6+5
3r=-14+5
3r=-9 Divided with 3
r=(-9)/3
r=-3
To find the value of r in the equation 5(r-1) = 2(r-4) - 6, you can follow these steps:
Step 1: Distribute the values inside the parentheses.
5r - 5 = 2r - 8 - 6
Step 2: Simplify the equation by combining like terms.
5r - 5 = 2r - 14
Step 3: Move all terms containing r to one side of the equation by subtracting 2r from both sides.
5r - 2r - 5 = -14
Step 4: Simplify the equation further.
3r - 5 = -14
Step 5: Move the constant term to the other side by adding 5 to both sides.
3r - 5 + 5 = -14 + 5
Step 6: Simplify the equation.
3r = -9
Step 7: Divide both sides of the equation by 3 to solve for r.
3r / 3 = -9 / 3
Step 8: Simplify the equation.
r = -3
Therefore, the value of r in the given equation is -3.