The Ksp for Ag2SO4 is 1.1x10^-5. Calculate the standard free energy change for silver sulfate dissolution at 25 degrees.
To calculate the standard free energy change (ΔG°) for the dissolution of silver sulfate (Ag2SO4) at 25 degrees Celsius, we need to use the equation:
ΔG° = -RT ln(K)
Where:
ΔG° = standard free energy change
R = gas constant (8.314 J/(mol·K))
T = temperature in Kelvin (25 degrees Celsius = 298 K)
K = equilibrium constant (Ksp in this case)
Given:
Ksp for Ag2SO4 = 1.1x10^-5
Let's substitute the values into the equation and calculate ΔG°:
ΔG° = - (8.314 J/(mol·K)) × 298 K × ln(1.1x10^-5)
First, let's solve the natural logarithm term within the parentheses:
ln(1.1x10^-5) ≈ - 11.5129
Now, let's substitute this value back into the equation:
ΔG° ≈ - (8.314 J/(mol·K)) × 298 K × (-11.5129)
Calculating further:
ΔG° ≈ 2.1654 kJ/mol
Therefore, the standard free energy change for the dissolution of silver sulfate at 25 degrees Celsius is approximately 2.1654 kJ/mol.