You need to prepare 500.00 mL of a 0.15 M solution of nitric acid . Concentrated nitric acid comes from the chemical copmanies as a 15.8 M liquid. How much (in mL) of this 15.8 M solution will you need to dilute to 500.00 mL to get the desired 0.15 M solution
mL x M = mL x M
when you get 600 substract 50 because that's what you start with
To calculate how much of the 15.8 M nitric acid solution you will need to dilute to obtain a 0.15 M solution, we can use the equation:
C1V1 = C2V2
Where:
C1 = Initial concentration (15.8 M)
V1 = Initial volume (unknown)
C2 = Final concentration (0.15 M)
V2 = Final volume (500.00 mL)
Rearranging the equation, we get:
V1 = (C2 * V2) / C1
Substituting the values, we have:
V1 = (0.15 M * 500.00 mL) / 15.8 M
V1 = 7.03 mL
Therefore, you will need to dilute 7.03 mL of the 15.8 M nitric acid solution to a final volume of 500.00 mL to obtain a 0.15 M solution.