Find the average kinetic energy per molecule of He at 30 degrees C
Isn't that (3/2)*RT divided by Avogadro's number.
No i'm sorry that is not being accepted as the right answer
http://galileo.phys.virginia.edu/classes/252/kinetic_theory.html
To find the average kinetic energy per molecule of helium (He) at 30 degrees Celsius, you can use the following formula:
Average kinetic energy per molecule = (3/2) * k * T
Where:
- (3/2) is a constant factor that represents the degrees of freedom of a monoatomic gas (such as helium) in three-dimensional space.
- k is the Boltzmann constant, approximately equal to 1.38 x 10^-23 joules per Kelvin.
- T is the temperature in Kelvin.
First, let's convert 30 degrees Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 30 + 273.15
T(K) = 303.15 K
Now we can substitute the values into the formula:
Average kinetic energy per molecule = (3/2) * (1.38 x 10^-23 J/K) * 303.15 K
Let's calculate the answer:
Average kinetic energy per molecule ≈ 6.16 x 10^-21 joules (J)
Therefore, the average kinetic energy per molecule of helium at 30 degrees Celsius is approximately 6.16 x 10^-21 J.