How many moles of HNO3 are present in 35.0 mL of a 2.60 M solution of nitric acid?
moles = M x L
To find how many moles of HNO3 are present in the given solution, you can use the formula:
moles = volume × concentration
Given:
Volume of the solution (V) = 35.0 mL
Concentration of the solution (C) = 2.60 M
First, let's convert the volume from milliliters (mL) to liters (L), as the concentration is in moles per liter (M):
Volume (V) = 35.0 mL = 35.0 mL × (1 L / 1000 mL) = 0.0350 L
Now, we can use the formula to find the number of moles:
moles (n) = volume (V) × concentration (C)
n = 0.0350 L × 2.60 mol/L
n ≈ 0.091 mol
Therefore, there are approximately 0.091 moles of HNO3 present in the 35.0 mL of a 2.60 M solution of nitric acid.