If a person does 80 J of work in moving a 30 \rm{kg} box over a 13 m distance on a horizontal surface, what is the minimum force required?
80=force*distance
you know distance, solve for force.
To find the minimum force required, we can use the equation:
Work = Force × Distance
Given:
Work (W) = 80 J
Distance (d) = 13 m
We can rearrange the equation to solve for the force (F):
Force = Work / Distance
Substituting the given values into the equation:
Force = 80 J / 13 m
Calculating:
Force ≈ 6.15 N
Therefore, the minimum force required to move the 30 kg box over a 13 m distance is approximately 6.15 N.
To find the minimum force required to move the box, we can use the formula:
$$\text{Work} = \text{Force} \times \text{Distance}$$
Given that the work done is 80 J (joules) and the distance is 13 m (meters), we can rearrange the formula to solve for force:
$$\text{Force} = \frac{\text{Work}}{\text{Distance}}$$
Plugging in the given values, we get:
$$\text{Force} = \frac{80 \, \text{J}}{13 \, \text{m}}$$
Now we can calculate the force by dividing 80 J by 13 m:
$$\text{Force} = 6.15 \, \text{N}$$
Therefore, the minimum force required to move the 30 kg box over a 13 m distance on a horizontal surface is approximately 6.15 N (newtons).