Question

How many moles of \rm HNO_3 are present in 40.0 mL of a 2.40 M solution of nitric acid?

Answer 1

I am not certain of you symbol \rm

Answer 2

I don't know \rm either, however, moles = M x L.

Answer 3

[AI-generated answer — Explain Bot]

To find the number of moles of HNO3 present in the solution, you can use the formula:

moles = (concentration in M) × (volume in L)

First, convert the volume of the solution from milliliters (mL) to liters (L):

40.0 mL = 40.0 mL ÷ 1000 mL/L = 0.04 L

Next, plug the given concentration and volume into the formula:

moles = 2.40 M × 0.04 L = 0.096 mol

Therefore, there are 0.096 moles of HNO3 present in 40.0 mL of a 2.40 M solution of nitric acid.