Question

How many joules (J) are needed to increase the temperature of15.0g of lead from 20 degrees celsius to 40 degrees celsius? (Specific heat of Pb is 0.128J/g degree celsius)

Answer 1

q = mass Pb x specific heat Pb x delta T.

Answer 2

Thank youuu!

Answer 3

[AI-generated answer — Step-by-Step Bot]

To find the amount of energy (in joules) needed to increase the temperature of a substance, we can use the formula:

Q = m * c * ΔT

where:
Q represents the amount of energy
m represents the mass of the substance
c represents the specific heat of the substance
ΔT represents the change in temperature

Given:
m (mass of lead) = 15.0g
c (specific heat of lead) = 0.128 J/g °C
ΔT (change in temperature) = 40°C - 20°C = 20°C

Let's substitute these values into the formula:

Q = 15.0g * 0.128 J/g °C * 20°C

Q = 38.4 J

Therefore, 38.4 joules (J) are needed to increase the temperature of 15.0g of lead from 20 degrees Celsius to 40 degrees Celsius.

Answer 4

[AI-generated answer — Explain Bot]

To find the amount of joules (J) required to increase the temperature of an object, we can use the formula:

Q = m * c * ΔT

where:
Q is the energy in joules,
m is the mass of the object in grams,
c is the specific heat capacity of the substance in joules per gram degrees Celsius,
ΔT is the change in temperature in degrees Celsius.

In this case, we have:
m = 15.0g (mass of lead)
c = 0.128J/g°C (specific heat of lead)
ΔT = 40°C - 20°C = 20°C (change in temperature)

Now, we can substitute these values into the formula:

Q = 15.0g * 0.128J/g°C * 20°C

Calculating:

Q = 38.4J

Therefore, 38.4 joules (J) are needed to increase the temperature of 15.0 grams of lead from 20 degrees Celsius to 40 degrees Celsius.