"Water flows over a section of Niagara Falls at the rate of 1.2*10^6 kg/s and falls 50.0m. How much power is generated by the falling water?"
It's a the kg/s that is confusing me. I don't know how to work with it.
Thanks, but I figured it out.
To determine the power generated by the falling water at Niagara Falls, you can use the following formula:
Power = (mass flow rate) x (acceleration due to gravity) x (height)
Given that the mass flow rate is 1.2 x 10^6 kg/s, the acceleration due to gravity is approximately 9.8 m/s^2, and the height is 50.0 m, we can substitute these values into the formula:
Power = (1.2 x 10^6 kg/s) x (9.8 m/s^2) x (50.0 m)
Now, let's calculate the power:
Power = 5.88 x 10^8 W
Therefore, the falling water generates a power of approximately 588 million watts.
To calculate the power generated by the falling water, you need to use the formula:
Power = Mass flow rate * gravitational acceleration * height
In this case, the mass flow rate is given as 1.2 * 10^6 kg/s, the gravitational acceleration is approximately 9.8 m/s^2, and the height is 50.0 m.
To work with the given mass flow rate, you can convert it to a more manageable unit by moving the decimal point. The number 1.2 × 10^6 can be written as 1,200,000. Therefore, the mass flow rate is 1,200,000 kg/s.
Now, you can substitute these values into the power formula:
Power = 1,200,000 kg/s * 9.8 m/s^2 * 50.0 m
Multiplying these values together, you will get the power generated by the falling water at Niagara Falls.